Advertisements
Advertisements
प्रश्न
Show that the following points taken in order to form an equilateral triangle
`"A"(sqrt(3), 2), "B"(0, 1), "C"(0, 3)`
Advertisements
उत्तर
Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
AB = `sqrt((0 - sqrt(3))^2 + (1 - 2)^2`
= `sqrt((- sqrt(3))^2 + (-1)^2`
= `sqrt(3 + 1)`
= `sqrt(4)`
= 2
BC = `sqrt((0 - 0)^2 + (3 - 1)^2`
= `sqrt(0^2 + 2^2)`
= `sqrt(4)`
= 2
AC = `sqrt((0 - sqrt(3))^2 + (3 - 2)^2`
= `sqrt((- sqrt(3))^2 + 1^2)`
= `sqrt(3 + 1)`
= `sqrt(4)`
= 2
AB = BC = AC ...(Three sides are equal)
∴ ABC is an equilateral triangle.
APPEARS IN
संबंधित प्रश्न
Find the distance with the help of the number line given below.
d (Q, B)
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = 1, y = 7
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = - 3, y = 7
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 4, 5
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
0, - 2
Co-ordinate of point P on a number line is - 7. Find the co-ordinates of points on the number line which are at a distance of 8 units from point P.
Find the distance between the following pair of points
(a, b) and (c, b)
Find the distance between the following pair of points
(3, −9) and (−2, 3)
Show that the following points taken in order to form an isosceles triangle
A(5, 4), B(2, 0), C(−2, 3)
The distance between the point (5, −1) and the origin is _________
