Advertisements
Advertisements
प्रश्न
Show that the following points taken in order to form an equilateral triangle
`"A"(sqrt(3), 2), "B"(0, 1), "C"(0, 3)`
Advertisements
उत्तर
Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
AB = `sqrt((0 - sqrt(3))^2 + (1 - 2)^2`
= `sqrt((- sqrt(3))^2 + (-1)^2`
= `sqrt(3 + 1)`
= `sqrt(4)`
= 2
BC = `sqrt((0 - 0)^2 + (3 - 1)^2`
= `sqrt(0^2 + 2^2)`
= `sqrt(4)`
= 2
AC = `sqrt((0 - sqrt(3))^2 + (3 - 2)^2`
= `sqrt((- sqrt(3))^2 + 1^2)`
= `sqrt(3 + 1)`
= `sqrt(4)`
= 2
AB = BC = AC ...(Three sides are equal)
∴ ABC is an equilateral triangle.
APPEARS IN
संबंधित प्रश्न
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = -4, y = -5
Sketch proper figure and write the answer of the following question.
If R-S-T and l(ST) = 3.7, l(RS) = 2.5, then l(RT) = ?
On a number line, the co-ordinates of P, Q, R are 3, -5 and 6 respectively. State with reason whether the following statement is true or false.
d(R, P) + d(P, Q) = d(R, Q)
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 4, 5
If P-Q-R and d(P, Q) = 3.4, d(Q, R)= 5.7 then d(P, R) = ?
Co-ordinate of point A on a number line is 1. What are the co-ordinates of points on the number line which are at a distance of 7 units from A?
Find the distance between the following pair of points
(3, 4) and (−7, 2)
Show that the following points taken in order to form an isosceles triangle
A(5, 4), B(2, 0), C(−2, 3)
A(−1, 1), B(1, 3) and C(3, a) are point and if AB = BC, then find ‘a’
Find the distance with the help of the number line given below.
d(J, H)
