Advertisements
Advertisements
प्रश्न
Show that:\[\sqrt[3]{- 125 - 1000} = \sqrt[3]{- 125} \times \sqrt[3]{- 1000}\]
Advertisements
उत्तर
LHS = \[\sqrt[3]{- 125 \times - 1000} = \sqrt[3]{- 5 \times - 5 \times - 5 \times - 10 \times - 10 \times - 10} = \sqrt[3]{\left\{ - 5 \times - 5 \times - 5 \right\} \times \left\{ - 10 \times - 10 \times - 10 \right\}} = - 5 \times - 10 = 50\]
RHS = \[\sqrt[3]{- 125} \times \sqrt[3]{- 1000} = \sqrt[3]{- 5 \times - 5 \times - 5} \times \sqrt[3]{\left\{ - 10 \times - 10 \times - 10 \right\}} = - 5 \times - 10 = 50\]
Because LHS is equal to RHS, the equation is true.
APPEARS IN
संबंधित प्रश्न
Find the smallest number by which the following number must be divided to obtain a perfect cube.
81
Write the cubes of 5 natural numbers which are of the form 3n + 1 (e.g. 4, 7, 10, ...) and verify the following:
'The cube of a natural number of the form 3n + 1 is a natural number of the same form i.e. when divided by 3 it leaves the remainder 1'.
By taking three different values of n verify the truth of the following statement:
If n is odd, then n3 is also odd.
Which of the following number is cube of negative integer - 64 .
Find the cube root of the following natural number 74088000 .
Show that:
\[\frac{\sqrt[3]{- 512}}{\sqrt[3]{343}} = \sqrt[3]{\frac{- 512}{343}}\]
Find the cube-root of -512
Find the cube-root of `-(27)/(125)`
Find the cube-root of -64 x -125
If a2 ends in 5, then a3 ends in 25.
