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प्रश्न
Represent the following pair of linear equations graphically and hence comment on the condition of consistency of this pair:
x – 5y = 6; 2x – 10y = 12
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उत्तर
1. Identify points for the first equation
For the equation x – 5y = 6
If y = 0, then x – 5(0) = 6
⇒ x = 6
Point: (6, 0)
If y = –2, then x – 5(–2) = 6
⇒ x + 10 = 6
⇒ x = –4
Point: (–4, –2)
If x = 11, then 11 – 5y = 6
⇒ –5y = –5
⇒ y = 1
Point: (11, 1)
2. Identify points for the second equation
For the equation 2x – 10y = 12:
If y = 0, then 2x – 10(0) = 12
⇒ 2x = 12
⇒ x = 6
Point: (6, 0)
If x = 1, then 2(1) – 10y = 12
⇒ 2 – 10y = 12
⇒ –10y = 10
⇒ y = –1
Notice that dividing the entire second equation by 2 gives x – 5y = 6, which is identical to the first equation.
Since both equations simplify to the same linear relationship, plotting them results in a single line on the coordinate plane.

4. Comment on the condition of consistency
To determine consistency algebraically, compare the ratios of the coefficients `(a_1)/(a_2), (b_1)/(b_2)` and `(c_1)/(c_2)` for equations in the form a1x + b1y = c1 and a2x + b2y = c2:
`(a_1)/(a_2) = 1/2`
`(b_1)/(b_2) = (-5)/(-10) = 1/2`
`(c_1)/(c_2) = 6/12 = 1/2`
Since `(a_1)/(a_2) = (b_1)/(b_2) = (c_1)/(c_2)`, the lines are coincident. This means every point on the line is a solution, resulting in infinitely many solutions. Therefore, the system is consistent and dependent.
