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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Prove the following: cos 2π15cos 4π15cos 8π15cos 16π15=116

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प्रश्न

Prove the following:

`cos  (2pi)/15 cos  (4pi)/15cos  (8pi)/15cos  (16pi)/15 = 1/16`

बेरीज
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उत्तर

L.H.S. = `cos  (2pi)/15 cos  (4pi)/15cos  (8pi)/15cos  (16pi)/15`

= `((2sin  (2pi)/15*cos  (2pi)/15)*cos  (4pi)/15*cos  (8pi)/15*cos  (16pi)/15)/(2sin  (2pi)/15)`

= `(sin  (4pi)/15*cos  (4pi)/15*cos  (8pi)/15*cos  (16pi)/15)/(2sin  (2pi)/15)`

= `((2sin  (4pi)/15*cos  (4pi)/15)cos  (8pi)/15*cos  (16pi)/15)/(4sin  (2pi)/15)`

= `(sin  (8pi)/15*cos  (8pi)/15*cos  (16pi)/15)/(4sin  (2pi)/15)`

= `((2sin  (8pi)/15*cos  (8pi)/15)cos  (16pi)/15)/(8sin  (2pi)/15)`

= `(sin  (16pi)/15*cos  (16pi)/15)/(8sin  (2pi)/15)`

= `(2sin  (16pi)/15*cos  (16pi)/15)/(16sin  (2pi)/15)`

= `(sin  (32pi)/15)/(16sin  (2pi)/15)`

= `(sin(2pi + (2pi)/15))/(16sin  (2pi)/15)`

= `(sin  (2pi)/15)/(16sin  (2pi)/15)`

= `1/16`

= R.H.S.

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पाठ 3: Trigonometry - 2 - Miscellaneous Exercise 3 [पृष्ठ ५७]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
पाठ 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q II. (3) | पृष्ठ ५७

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