Advertisements
Advertisements
प्रश्न
Prove that Δ∇ = Δ – ∇
बेरीज
Advertisements
उत्तर
L.H.S = Δ∇
= (E – 1)(1 – E–1)
= E – EE–1 + E–1
= E – 1 – 1 – E–1
= E – 2 – E–1 .........(1)
R.H.S = Δ – ∇
= (E – 1) – (1 – E–1)
= E – 1 – 1 + E–1
= E – 2 + E–1 ........(2)
From (1) and (2)
L.H.S = R.H.S
Hence proved.
shaalaa.com
Finite Differences
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
If y = x3 – x2 + x – 1 calculate the values of y for x = 0, 1, 2, 3, 4, 5 and form the forward differences table
If f(x) = x2 + 3x than show that Δf(x) = 2x + 4
Find the missing entries from the following.
| x | 0 | 1 | 2 | 3 | 4 | 5 |
| y = f(x) | 0 | - | 8 | 15 | - | 35 |
Choose the correct alternative:
Δf(x) =
Choose the correct alternative:
If c is a constant then Δc =
Choose the correct alternative:
If ‘n’ is a positive integer Δn[Δ-n f(x)]
Choose the correct alternative:
E f(x) =
Choose the correct alternative:
∇ ≡
Choose the correct alternative:
∇f(a) =
Prove that EV = Δ = ∇E
