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Prove that the following statement pattern is a tautology. (p → q) ↔ (~ q → ~ p) - Mathematics and Statistics

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प्रश्न

Prove that the following statement pattern is a tautology.

(p → q) ↔ (~ q → ~ p)

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उत्तर

p q ~p ~q p→q ~q→~p (p→q)↔(~q→~p)
T T F F T T T
T F F T F F T
F T T F T T T
F F T T T T T

All the truth values in the last column are T. Hence, it is a tautology.

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पाठ 1: Mathematical Logic - Exercise 1.6 [पृष्ठ १६]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 1 Mathematical Logic
Exercise 1.6 | Q 3.2 | पृष्ठ १६

संबंधित प्रश्‍न

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( p ∧  ∼ r ) ∧ ( ∼ q ∧ s )


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Using the truth table, prove the following logical equivalence.

p ∧ (q ∨ r) ≡ (p ∧ q) ∨ (p ∧ r)


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p → (q ∧ r) ≡ (p ∧ q) (p → r)


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(∼ p → q) ∧ (p ∧ r)


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[(p ∨ q) ∧ ∼p] ∧ ∼q


Prepare truth tables for the following statement pattern.

p → (~ p ∨ q)


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(~p ∧ q) ∧ (~q ∨ ~r)


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"If it snows, then they do not drive the car"


With proper justification, state the negation of the following.

(p → q) ∨ (p → r)


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(~p ∨ q) ∧ (~p ∧ ~q)


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[p → (~q ∨ r)] ↔ ~[p → (q → r)]


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p ∧ (q ∨ r) ≡ (p ∧ q) ∨ (p ∧ r)


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(p ∧ ~q) ∨ (~ p ∧ q) ≡ (p ∨ q) ∧ ~(p ∧ q)


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(p ∧ q) ∧ r ≡ p ∧ (q ∧ r)


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[p → (~ q ˅ r)] ↔ ~[p → (q → r)] is a tautology, contradiction or contingency.


Which of the following is not equivalent to p → q.


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