Advertisements
Advertisements
प्रश्न
Prove that (5x - 4) is a factor of the polynomial f(x) = 5x3 - 4x2 - 5x +4. Hence factorize It completely.
Advertisements
उत्तर
If 5x - 4 is assumed to be factor, then x = `4/5` . Substituting this in problem polynomial, we get:
`"f"(4/5) = 5 xx (4/5) xx (4/5) xx (4/5) - 4 xx (4/5) xx (4/5) - 5 xx (4/5) + 4`
`= 64/25 - 64/25 - 4 + 4`
= 0
Hence (5x - 4) is a factor of the polynomial.
Multiplying (5x-4) by x2, we get 5x3 - 4x2, hence we are left with -5x + 4 (and 1st part of factor as x2).
Multiplying (5x - 4) by -1, we get -5x + 4, hence we are left with 0 (and 2nd part of factor as -7x).
Hence complete factor is (5x - 4) (x2-1).
Further factorizing (x2 - 1), we get :
⇒ (x - 1)(x + 1) = 0
Hence answer is (5x - 4)(x - 1)(x + 1) = 0
APPEARS IN
संबंधित प्रश्न
If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.
Prove by factor theorem that
(2x+1) is a factor of 4x3 + 12x2 + 7x +1
Prove by factor theorem that
(x - 3) is a factor of 5x2 - 21 x +18
Use the factor theorem to factorise completely x3 + x2 - 4x - 4.
Show that 2x + 7 is a factor of 2x3 + 5x2 – 11x – 14. Hence factorise the given expression completely, using the factor theorem.
If (2x + 1) is a factor of 6x3 + 5x2 + ax – 2 find the value of a.
What number should be subtracted from 2x3 – 5x2 + 5x so that the resulting polynomial has 2x – 3 as a factor?
Find the value of the constants a and b, if (x – 2) and (x + 3) are both factors of the expression x3 + ax2 + bx – 12.
If (2x – 3) is a factor of 6x2 + x + a, find the value of a. With this value of a, factorise the given expression.
Determine whether (x – 1) is a factor of the following polynomials:
x3 + 5x2 – 10x + 4
