मराठी

Prove that secθ-1secθ+1=(sinθ1+cosθ)2

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प्रश्न

Prove that  `(sec theta - 1)/(sec theta + 1) = ((sin theta)/(1 + cos theta))^2` 

बेरीज
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उत्तर

`(sec theta - 1)/(sec theta + 1)`

`= (1/cos theta - 1)/(1/cos theta + 1)`

= `((1 - cos theta)/cos theta)/((1 + cos theta)/cos theta)`

`= (1 - cos theta)/(1 +cos theta)`

`= (1 - cos theta)/(1 + cos theta) xx (1 + cos theta)/(1+ cos theta)`

`= (1 - cos^2 theta)/(1 + cos theta)^2`

`= sin^2 theta/(1 + cos theta)^2`

`= [sin theta/(1 + cos theta)]^2`

=RHS

Hence proved.

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पाठ 11: Trigonometric Identities - Exercise 11.1 [पृष्ठ ४७]

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आर.डी. शर्मा Mathematics [English] Class 10
पाठ 11 Trigonometric Identities
Exercise 11.1 | Q 83.4 | पृष्ठ ४७
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