Advertisements
Advertisements
प्रश्न
Prove that if a number is trebled then its cube is 27 times the cube of the given number.
Advertisements
उत्तर
Let us consider a number n. Then its cube would be \[n^3\] .
If the number n is trebled, i.e., 3n, we get:
\[\left( 3n \right)^3 = 3^3 \times n^3 = 27 n^3\]
It is evident that the cube of 3n is 27 times of the cube of n.
Hence, the statement is proved.
APPEARS IN
संबंधित प्रश्न
Find the smallest number by which the following number must be multiplied to obtain a perfect cube.
256
Find the cubes of the number 21 .
Write true (T) or false (F) for the following statement:
If a and b are integers such that a2 > b2, then a3 > b3.
Multiply 210125 by the smallest number so that the product is a perfect cube. Also, find out the cube root of the product.
What is the smallest number by which 8192 must be divided so that quotient is a perfect cube? Also, find the cube root of the quotient so obtained.
Making use of the cube root table, find the cube root
700
Find if the following number is a perfect cube?
588
Find the cube-root of 250.047
The smallest number to be added to 3333 to make it a perfect cube is ___________
`root(3)(1000)` is equal to ______.
