Advertisements
Advertisements
प्रश्न
Prove that following numbers are irrationals:
\[4 + \sqrt{2}\]
संख्यात्मक
Advertisements
उत्तर
Let us assume that `4+sqrt2` is rational .Then , there exist positive co primes a and bsuch that
`4+sqrt2=a/b`
`sqrt2=a/b-4`
`sqrt=(a-4b)/b`
`sqrt2` is a rational numbers which is a contradication.
Hence \[4 + \sqrt{2}\] is irrational
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
