Advertisements
Advertisements
प्रश्न
Prove that `(cos(90 - "A"))/(sin "A") = (sin(90 - "A"))/(cos "A")`
Advertisements
उत्तर
L.H.S = `(cos(90 - "A"))/(sin "A")`
= `"sin A"/"sin A"`
= 1
R.H.S = `(sin(90 - "A"))/(cos "A")`
= `"cos A"/"cos A"`
= 1
∴ L.H.S = R.H.S
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities.
tan2 θ − sin2 θ = tan2 θ sin2 θ
Prove the following trigonometric identities.
`(cot^2 A(sec A - 1))/(1 + sin A) = sec^2 A ((1 - sin A)/(1 + sec A))`
if `cosec theta - sin theta = a^3`, `sec theta - cos theta = b^3` prove that `a^2 b^2 (a^2 + b^2) = 1`
Given that:
(1 + cos α) (1 + cos β) (1 + cos γ) = (1 − cos α) (1 − cos α) (1 − cos β) (1 − cos γ)
Show that one of the values of each member of this equality is sin α sin β sin γ
Show that : `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec A cosec A`
Prove the following identities:
cosec4 A (1 – cos4 A) – 2 cot2 A = 1
If sin A + cos A = p and sec A + cosec A = q, then prove that : q(p2 – 1) = 2p.
`(1 + cot^2 theta ) sin^2 theta =1`
`sin^6 theta + cos^6 theta =1 -3 sin^2 theta cos^2 theta`
Find the value of `(cos 38° cosec 52°)/(tan 18° tan 35° tan 60° tan 72° tan 55°)`
What is the value of (1 + tan2 θ) (1 − sin θ) (1 + sin θ)?
If 5x = sec θ and \[\frac{5}{x} = \tan \theta\]find the value of \[5\left( x^2 - \frac{1}{x^2} \right)\]
The value of sin2 29° + sin2 61° is
Prove the following identity :
`(cosA + sinA)^2 + (cosA - sinA)^2 = 2`
Prove the following identity :
`sqrt((1 + cosA)/(1 - cosA)) = cosecA + cotA`
Prove the following identity :
`(secθ - tanθ)^2 = (1 - sinθ)/(1 + sinθ)`
Find the value of x , if `cosx = cos60^circ cos30^circ - sin60^circ sin30^circ`
Prove that `sqrt((1 + sin θ)/(1 - sin θ))` = sec θ + tan θ.
If tan θ + cot θ = 2, then tan2θ + cot2θ = ?
If cos 9α = sinα and 9α < 90°, then the value of tan5α is ______.
