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Prove that the average power taking by a pure capacitor fed with a sinusoidal ac supply in a circuit is zero.
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PHASE DIFFERENCE
It is the angle between the voltage and current phasors.
ЁЭЬС = 90°
POWER FACTOR
It is defined as the cosine of the angle between the voltage and current phasors.
Pf = cosЁЭЬС = cos(90°) = 0
POWER
Instantaneous power P is given by,
ЁЭСЭ = ЁЭСгЁЭСЦ
ЁЭСЭ = ЁЭСЙЁЭСЪЁЭСаЁЭСЦЁЭСЫЁЭЬФЁЭСбЁЭР╝ЁЭСЪsin (ЁЭЬФЁЭСб + 90)
ЁЭСЭ = ЁЭСЙЁЭСЪЁЭР╝ЁЭСЪЁЭСаЁЭСЦЁЭСЫЁЭЬФЁЭСбЁЭСРЁЭСЬЁЭСаЁЭЬФЁЭСб

ЁЭСЭ =`(V_mI_m)/2`ЁЭСаЁЭСЦЁЭСЫ2ЁЭЬФЁЭСб
The average power for one complete cycle, P =0
Hence, power consumed by a purely capacitive circuit is zero.
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