मराठी

Prove that 5sqrt(2) is an irrational number, given that sqrt(2) is an irrational number.

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प्रश्न

Prove that `5sqrt(2)` is an irrational number, given that `sqrt(2)` is an irrational number.

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उत्तर

Given: `sqrt(2)` is an irrational number.

To Prove: `5sqrt(2)` is an irrational number.

Proof [Step-wise]:

1. Assume, for contradiction, that `5sqrt(2)` is rational.

2. Then there exist integers a and b (b ≠ 0) with gcd(a, b) = 1 such that `5sqrt(2) = a/b`.

3. Divide both sides by 5 to get `sqrt(2) = a/(5b)`. The right-hand side `a/(5b)` is a rational number (ratio of integers).

4. This implies `sqrt(2)` is rational, which contradicts the given that `sqrt(2)` is irrational.

5. Therefore, the assumption in step 1 is false, so `5sqrt(2)` is not rational (i.e., it is irrational).

Hence, given `sqrt(2)` is irrational, `5sqrt(2)` is also irrational.

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पाठ 1: Real Numbers - EXERCISE 1D [पृष्ठ ३६]

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 1 Real Numbers
EXERCISE 1D | Q 11. | पृष्ठ ३६
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