Question

Prove that:

3 cosec² 60°  - 2 cot² 30°  + sec² 45°  = 0

Answer 1

LHS =3 cosec²60° – 2 cot²30° + sec²45°

=`3(2/sqrt3)^2 – 2(sqrt3)^2 + (sqrt2)^2`

= `3xx4/3-2xx3+2`

= 4 – 6 + 2

= 0

= RHS