Advertisements
Advertisements
प्रश्न
Pritam bought a plot of land for Rs 640000. Its value is increasing by 5% of its previous value after every six months. What will be the value of the plot after 2 years?
Advertisements
उत्तर
Given:
P = Rs 64, 000
R = 5 % for every six months
Value of the plot after two years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[ \Rightarrow 64, 000 \left( 1 + \frac{5}{200} \right)^4 \]
\[ = 64, 000 \left( 1 . 025 \right)^4 \]
\[ = 706, 440 . 25\]
Thus, the value of the plot after two years will be Rs 706, 440.25.
APPEARS IN
संबंधित प्रश्न
The population of a place increased to 54000 in 2003 at a rate of 5% per annum Find the population in 2001.
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 5%, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 3000, Rate = 18%, Time = 2 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 12800, Rate = \[7\frac{1}{2} %\], Time = 3 years
Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 4%, 5% and 3% respectively, find the present population.
The population of a town increases at the rate of 50 per thousand. Its population after 2 years will be 22050. Find its present population.
The population of a city increases each year by 4% of what it had been at the beginning of each year. If the population in 1999 had been 6760000, find the population of the city in (i) 2001 (ii) 1997.
Mohan purchased a house for Rs 30000 and its value is depreciating at the rate of 25% per year. Find the value of the house after 3 years.
In a forest there are 40,000 trees. Find the expected number of trees after 3 years if the objective is to increase the number at the rate 5% per year.
