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Predict Which of the Following Reaction Will Have the Appreciable Concentration of Reactants and Products:

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प्रश्न

Predict which of the following reaction will have the appreciable concentration of reactants and products:

  1. \[\ce{Cl2 (g) ⇌ 2Cl (g)}\] Kc = 5 ×10–39
  2. \[\ce{Cl2 (g) + 2NO (g) ⇌ 2NOCl (g)}\] Kc = 3.7 × 108
  3. \[\ce{Cl2 (g) + 2NO2 (g) ⇌ 2NO2Cl (g)}\] Kc = 1.8
टीपा लिहा
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उत्तर

Following conclusions can be drawn from the values of Kc .

  1. Since the value of Kc is very small, this means that the molar concentration of the products is very small as compared to that of the reactants.
  2. Since the value of Kc is quite large, this means that the molar concentration of the products is very large as compared to that of the reactants
  3. Since the value of Kc is 1.8, this means that both the products and reactants have appreciable concentration.
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Law of Chemical Equilibrium and Equilibrium Constant
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पाठ 6: Equilibrium - EXERCISES [पृष्ठ २३६]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 11
पाठ 6 Equilibrium
EXERCISES | Q 7.32 | पृष्ठ २३६

संबंधित प्रश्‍न

Write the expression for the equilibrium constant, Kc for each of the following reactions:

\[\ce{2NOCl (g) ⇌ 2NO (g) + Cl2 (g)}\]


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\[\ce{CH3COOC2H5(aq) + H2O(l) ⇌CH3COOH (aq) + C2H5OH (aq)}\]


At 700 K, the equilibrium constant for the reaction

\[\ce{H_{2(g)} + I_{2(g)} ↔ 2HI_{(g)}}\] 

is 54.8. If 0.5 molL–1 of HI(g) is present at equilibrium at 700 K, what are the concentration of H2(g) and I2(g) assuming that we initially started with HI(g) and allowed it to reach equilibrium at 700 K?


Does the number of moles of reaction products increase, decrease or remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume?

\[\ce{3Fe (s) + 4H2O (g) ⇌ Fe3O4 (s) + 4H2 (g)}\]


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At 500 K, equilibrium constant, \[\ce{K_c}\], for the following reaction is 5.

\[\ce{1/2 H2 (g) + 1/2 I2 (g) ⇌ HI (g)}\]

What would be the equilibrium constant \[\ce{K_c}\] for the reaction

\[\ce{2HI (g) ⇌ H2 (g) + I2 (g)}\]


For the reaction : \[\ce{N2 (g) + 3H2 (g) ⇌ 2NH3 (g)}\]

Equilibrium constant `K_C = ([NH3]^2)/([N_2][H_2]^3)`

Some reactions are written below in Column I and their equilibrium constants in terms of Kc are written in Column II. Match the following reactions with the corresponding equilibrium constant

Column I (Reaction) Column II (Equilibrium constant)
(i) \[\ce{2N2 (g) + 6H2 (g) ⇌ 4NH3 (g)}\] (a) `2K_c`
(ii) \[\ce{2NH3 (g) ⇌ N2 (g) + 3H2 (g)}\] (b) `K_c^(1/2)`
(iii) \[\ce{1/2 N2 (g) + 3/2 H2 (g) ⇌ NH3 (g)}\] (c) `1/K_c`
  (d) `K_c^2`

Match standard free energy of the reaction with the corresponding equilibrium constant.

Column I Column II
(i) ∆GΘ > 0 (a) K > 1
(ii) ∆GΘ > 0  (b) K = 1
(iii) ∆GΘ = 0 (c) K = 0
  (d) K < 1

For the reaction,

\[\ce{N2 + O2(g) ⇌ 2NO(g)}\]

the equilibrium constant is K1. The equilibrium constant is K2 for the reaction

\[\ce{2NO(g) + O2(g) ⇌ 2NO2(g)}\]

What is "K" for the reaction:

\[\ce{NO2(g) ⇌ 1/2 N2(g) + O2(g)}\]?


At 1990 K and 1 atm pressure, there are equal numbers of Cl2 molecules and Cl atoms in the reaction mixture. The value of Kp for the reaction Cl2(g) ⇌ 2Cl(g) under the above conditions is x × 10−1. The value of x is ______. (Rounded-off to the nearest integer)


For the reaction \[\ce{A(g) <=> B(g)}\] at 495 K, ΔG° = −9.478 kJ mol−1

If we start the reaction in a closed container at 495 K with 22 millimoles of A, the amount of B in the equilibrium mixture is ______ millimoles. (Round off to the Nearest Integer).

[R = 8.314 J mol−1 K−1; ln 10 = 2.303]


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For which of the following Kp is less than Kc?


The equilibrium constant for the reaction is ______ × 1026.

\[\ce{Fe + CuSO4 <=> FeSO4 + Cu}\] at 25°C.

Given `"E"_("Fe"//"Fe"^(2+))^0` = 0.44 V

`"E"_("Cu"//"Cu"^(2+))^0` = - 0.337 V


In which one of the following equilibria, KP ≠ Kc?


In which of the following equilibria, Kp and Kc are not equal?


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