Question

PQ is a long straight conductor carrying a current of 3A as shown in Figure below. An electron moves with a velocity of 2 x 10⁷ ms^-1 parallel to it. Find the force acting on the electron.

Answer 1

   q = 1.6  × 10^-19  C, i=3 A, r = 0. 6 m
   v = 2 x 10⁷ ms^-1
  θ = 90°
`bar(B) = 10^-7 xx (2xx3)/0.6`
∴  Force on electron, \[\overrightarrow{F }\] = q v B sin  θ
                                  \[\overrightarrow{F }\] = 1.6 x 10^-19  x 2 x 10⁷ x 10⁷. `6/0.6`
                                  \[\overrightarrow{F }\]= 3.2 x 10^-18 N