Advertisements
Advertisements
प्रश्न
Perform the following division:
(x3y3 + x2y3 – xy4 + xy) ÷ xy
Advertisements
उत्तर
We have,
(x3y3 + x2y3 – xy4 + xy) ÷ xy
= `(x^3y^3 + x^2y^3 - xy^4 + xy)/(xy)`
= `(x^3y^3)/(xy) + (x^2y^3)/(xy) - (xy^4)/(xy) + (xy)/(xy)`
= `(x xx x xx x xx y xx y xx y)/(x xx y) + (x xx x xx y xx y xx y)/(x xx y) - (x xx y xx y xx y xx y)/(x xx y) + ( x xx y)/(x xx y)`
= x2y2 + xy2 – y3 + 1
APPEARS IN
संबंधित प्रश्न
Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`
Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 9.8 × 10.2
Simplify the following using the identities: \[\frac{198 \times 198 - 102 \times 102}{96}\]
Find the following product: (2x2 − 3) (2x2 + 5)
Evaluate the following: 34 × 36
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(2x + 3)(2x – 5)(2x – 6)
If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x2 + y2 + z2
Multiply the following:
(3x2 + 4x – 8), (2x2 – 4x + 3)
Expand the following, using suitable identities.
(0.9p – 0.5q)2
