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प्रश्न
Perform the following division:
(x3y3 + x2y3 – xy4 + xy) ÷ xy
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उत्तर
We have,
(x3y3 + x2y3 – xy4 + xy) ÷ xy
= `(x^3y^3 + x^2y^3 - xy^4 + xy)/(xy)`
= `(x^3y^3)/(xy) + (x^2y^3)/(xy) - (xy^4)/(xy) + (xy)/(xy)`
= `(x xx x xx x xx y xx y xx y)/(x xx y) + (x xx x xx y xx y xx y)/(x xx y) - (x xx y xx y xx y xx y)/(x xx y) + ( x xx y)/(x xx y)`
= x2y2 + xy2 – y3 + 1
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