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प्रश्न
Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is ______.
पर्याय
205 pm
185 pm
260 pm
175 pm
MCQ
रिकाम्या जागा भरा
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उत्तर
Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is 175 pm.
Explanation:
Given: a = 495 pm
Radius, r = ?
For fee structure
radius = r = `a/(2sqrt2) = 495/(2sqrt2) = 175` cm
The radius of the Cu atom = is 175 pm.
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