Advertisements
Advertisements
प्रश्न
Ordinary chlorine gas has two isotopes \[\ce{^35_17Cl}\] and \[\ce{^37_17Cl}\] in the ratio of 3 : 1. Calculate the relative atomic mass of chlorine.
संख्यात्मक
Advertisements
उत्तर
\[\ce{^35_17Cl : ^37_17Cl}\] = 3 : 1
∴ Total mass = (35 × 3) + (37 × 1)
= 105 + 37
= 142
∴ Relative atomic mass of chlorine = `142/4`
= 35.5
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
