मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

One hundred and twenty five small liquid drops, each carrying a charge of 0.5 µC and of diameter 0.1 m form a bigger drop. Calculate the potential at the surface of the bigger drop. - Physics

Advertisements
Advertisements

प्रश्न

One hundred and twenty five small liquid drops, each carrying a charge of 0.5 µC and of diameter 0.1 m form a bigger drop. Calculate the potential at the surface of the bigger drop.

संख्यात्मक
Advertisements

उत्तर

Given: n = 125, q = 0.5 x 10-6 C, d = 0.1 m

To find: Electrical Potential (V) =?

Formula: `V = Q/(4piε_0P)`

The radius of each small drop, r = d/2 = 0.05 m

The volume of the larger drop being equal to the volume of the n smaller drops, the radius of the larger drop is

R = `root(3)("nr") = root(3)(125) (0.05) = 5 xx 0.05 = 0.25` m

The charge applied on the larger drop,

Q = nq = 125 × (0.5 × 10-6) C

∴ The electric potential of the surface of the larger drop,

V = `1/(4piε_0) "Q"/"R" = (9 xx 10^9) xx (125 xx (0.5 xx 10^-6))/0.25`

= 9 × 125 × 2 × 103 = 2.25 × 106

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Electrostatics - Exercises [पृष्ठ २१३]

APPEARS IN

बालभारती Physics [English] Standard 12 Maharashtra State Board
पाठ 8 Electrostatics
Exercises | Q 9 | पृष्ठ २१३

संबंधित प्रश्‍न

A charge 6 µC is placed at the origin and another charge - 5 µC is placed on the y-axis at A = (0, 6.0 m). 


(a) Calculate the net electric potential at P = (8.0 m, 0).
(b) Calculate the work done in bringing a proton from infinity to point P. What is the significance of the negative sign?


Which physical quantity has its unit as J/C? Is it a scalar or vector?


Find the electric potential at the surface of an atomic nucleus (Z = 50) of radius 9 × 10-13 cm.  


Three-point charges +q, +2q and Q are placed at the three vertices of an equilateral triangle. Find the value of charge Q (in terms of q), so that the electric potential energy of the system is zero. 


Derive an expression for the electric potential due to an electric dipole.


An AC circuit contains resistance of 12Q and inductive reactance 5Q. The phase angle between current and potential difference will be ______.


In a certain region of space with volume 0.2 m3 , the electric potential is found to be 5V throughout. The magnitude of electric field in this region is: ____________.


The electric potential V at any point O (x, y, z all in metres) in space is given by V = 4x2 volt. The electric field at the point (1 m, 0, 2m) in volt/metre is ____________.


Two parallel plates separated by a distance 'd' are kept at potential difference 'V' volt. A charge 'q' of mass 'm' enters in parallel plates with some velocity. The acceleration of the charged particle will be ______ 


A capacitor C1 = 4µF is connected is series with another capacitor C2 = 1µF. The combination is connected across d.c. source of 200 V. The ratio of potential across C2 to that across C1 is ______.


In the circuit shown, the potential difference across the 4.5 µF capacitor is ______.


Potential energy as a function of r is given by U =  `"A"/"r"^10-"B"/"r"^5`, where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be ______.


A semicircular wire of radius a having λ as charge per unit length is shown in the figure. Find the electric potential at the centre of the semicircular wire. 


State the formula giving the relation between electric field intensity and potential gradient.


1 Weber/second is equal to ______.


Derive an expression for the electric potential energy of an electric dipole in a uniform electric field.


Derive the relation between electric intensity and electric potential. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×