Advertisements
Advertisements
प्रश्न
On what sum of money will the difference between the compound interest and simple interest for 2 years be equal to Rs. 25 if the rate of interest charged for both is 5% p.a.?
Advertisements
उत्तर
C.I = `P[(1 + r/100)^2 - 1] = P[(1 + 5/100)^2 - 1] = "41P"/400`
`S.I = (P xx 5 xx 2)/100 = P/100`
Given, C.I. - S.I. Rs. 25
`=> "41P"/400 - P/10 = 25`
`=> (41P - 40P)/400 = 25`
`=> P = 10000`
∴ Required sum = Rs. 10,000
APPEARS IN
संबंधित प्रश्न
If a, b, c are in continued proportion, prove that (a + b + c) (a – b + c) = a2 + b2 + c2
A sum of Rs. 65000 is invested for 3 years at 8 % p.a. compound interest.
Find the compound interest earned in the first two years.
Alisha invested Rs 75000 for 4 years at 8 % p.a. compound interest,
Find the interest earned in the third year.
Natasha gave Rs.6O,OOO to Nimish for 3 years at 15%,p.a. compound interest.
Calculate to the nearest rupee :
The amount Natasha receives at the end of 3 years.
Natasha gave Rs.6O,OOO to Nimish for 3 years at 15%,p.a. compound interest.
Calculate to the nearest rupee :
The Compound Interest paid by Nimish
Calculate the amount and the compound interest on :
Rs. 6,000 in 3 years at 5% per year.
Calculate the difference between the simple interest and the compound interest on Rs. 4,000 in 2 years at 8% per annum compounded yearly.
A man lends Rs. 12,500 at 12% for the first year, at 15% for the second year and at 18% for the third year. If the rates of interest are compounded yearly ; find the difference between the C.I. fo the first year and the compound interest for the third year.
The population of a town 2 years ago was 62,500. Due to migration to cities, it decreases at the rate of 4% per annum. Find its present population.
Mr. Kumar borrowed Rs. 15,000 for two years. The rate of interest for the two successive years are 8% and 10% respectively. If he repays Rs. 6,200 at the end of the first year, find the outstanding amount at the end of the second year.
