मराठी

On the basis of Bohr's theory, derive an expression for the radius of the nth orbit of an electron of hydrogen atom.

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प्रश्न

On the basis of Bohr's theory, derive an expression for the radius of the nth orbit of an electron of hydrogen atom.

व्युत्पत्ती
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उत्तर

Let r be the orbit's radius and e, m, and v represent the electron's charge, mass, and velocity. Ze represents the nucleus's positive charge. For an atom of hydrogen, Z = 1. The electrostatic force of attraction provides centripetal force.
Therefore,

`(mv^2)/r = 1/(4piε_0) (Ze xx e)/ r^2`

`mv^2 = (Ze^2)/(4piε_0r)`  ...(i)

By first postulate:

`mvr = (nh)/(2pi)`  ...(ii)

Where n is the quantum number.

Squaring equation (ii) and dividing by equation (i), we get:

`(m^2v^2r^2)/(mv^2) = (n^2h^2)/((4pi^2)/((Ze^2)/(4piε_0r)))`

Then, `r = (n^2h^2ε_0)/(piZe^2m)`

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Calculate the radius of second Bohr orbit in hydrogen atom from the given data.

Mass of electron = 9.1 x 10-31kg

Charge on the electron = 1.6 x 10-19 C

Planck’s constant = 6.63 x 10-34 J-s.

Permittivity of free space = 8.85 x 10-12 C2/Nm2


Explain, giving reasons, which of the following sets of quantum numbers are not possible.

  1. n = 0, l = 0, ml = 0, ms = + ½
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  4. n = 2, l = 1, ml = 0, ms = – ½
  5. n = 3, l = 3, ml = –3, ms = + ½
  6. n = 3, l = 1, ml = 0, ms = + ½

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(A) – 1

(B) 2

(C) 1/2

(D) – 0.5


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