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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Obtain the differential equation by eliminating arbitrary constants from the following equation. y2 = (x + c)3 - Mathematics and Statistics

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प्रश्न

Obtain the differential equation by eliminating arbitrary constants from the following equation.

y2 = (x + c)3

बेरीज
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उत्तर

y2 = (x + c)3       ...(i)

Differentiating w.r.t. x, we get

`2y dy/dx = 3 (x+c)^2`        ...(ii)

Dividing (i) by (ii), we get

`y^2/(2y(dy/dx)) = ((x+c)^3)/(3(x+c)^2)`

∴ `y/(2(dy/dx)) = (x+c)/3`

∴ `x+c = (3y)/(2(dy/dx))`

∴ `c=-x +(3y)/(2(dy/dx))`

Substituting the value of c in (i), we get

`y^2 = [x+(-x+(3y)/(2(dy/dx)))]^3`

= `((3y)/(2(dy/dx)))^3`

∴ `y^2 = (27y^3)/(8(dy/dx)^3`

∴ `(dy/dx)^3 = (27y)/8`

∴ `dy/dx = 3/2root3y`

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Formation of Differential Equation by Eliminating Arbitary Constant
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Differential Equation and Applications - Exercise 8.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 8 Differential Equation and Applications
Exercise 8.2 | Q 1.5 | पृष्ठ १६३
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