Advertisements
Advertisements
प्रश्न
National Art convention got registrations from students from all parts of the country, of which 60 are interested in music, 84 are interested in dance and 108 students are interested in handicrafts. For optimum cultural exchange, organisers wish to keep them in minimum number of groups such that each group consists of students interested in the same artform and the number of students in each group is the same. Find the number of students in each group. Find the number of groups in each art form. How many rooms are required if each group will be allotted a room?
Advertisements
उत्तर
Number of students in each group subject to the given condition = HCF (60, 84, 108)
HCF (60, 84, 108) = 12
Number of groups in Music = `60/12` = 5
Number of groups in Dance = `84/12` = 7
Number of groups in Handicrafts = `108/12` = 9
Total number of rooms required = 21
APPEARS IN
संबंधित प्रश्न
Find the LCM and HCF of the following integers by applying the prime factorisation method:
40, 36 and 126
If m, n are natural numbers, for what values of m, does 2n × 5m ends in 5?
If p1x1 × p2x2 × p3x3 × p4x4 = 113400 where p1, p2, p3, p4 are primes in ascending order and x1, x2, x3, x4, are integers, find the value of p1, p2, p3, p4 and x1, x2, x3, x4
The sum of the exponents of the prime factors in the prime factorization of 1729 is
The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is ______.
On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm and 45 cm, respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?
Find the HCF and LCM of 72 and 120.
Assertion (A): The HCF of two numbers is 5 and their product is 150. Then their LCM is 40.
Reason(R): For any two positive integers a and b, HCF (a, b) × LCM (a, b) = a × b.
The HCF of the smallest 2-digit number and the smallest composite number is ______.
The prime factorisation of the number 5488 is ______.
