Advertisements
Advertisements
प्रश्न
Multiply the following:
b3, 3b2, 7ab5
Advertisements
उत्तर
We have,
b3, 3b2 and 7ab5
∴ b3 × 3b2 × 7ab5 = (1 × 3 × 7)b3 × b2 × ab5
= 21ab10
APPEARS IN
संबंधित प्रश्न
Multiply the binomials.
(2x + 5) and (4x − 3)
Multiply the binomials.
`(3/4 a^2 + 3b^2) and 4(a^2 - 2/3 b^2)`
Find the product.
(a2 + b) (a + b2)
Multiply the monomial by the binomial and find the value for x = −1, y = 0.25 and z = 0.05: −3x(y2 + z2)
Multiply the monomial by the binomial and find the value for x = −1, y = 0.25 and z = 0.05: z2(x − y)
Multiply the monomial by the binomial and find the value for x = −1, y = 0.25 and z = 0.05:
xz(x2 + y2)
Find the product of the following binomial: (2x + y)(2x + y)
Find the product of the following binomial: \[\left( x^4 + \frac{2}{x^2} \right)\left( x^4 - \frac{2}{x^2} \right)\]
Using the formula for squaring a binomial, evaluate the following: (99)2
Using the formula for squaring a binomial, evaluate the following: (999)2
