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प्रश्न
Multiply: abx, −3a2x and 7b2x3
बेरीज
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उत्तर
abx × −3a2x × 7b2x3
= (−3×7) (a ×a2) (b × b2) (x × x × x3)
= −21a3b3x5
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संबंधित प्रश्न
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
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Solve: (-12x) × 3y2
Multiply the following:
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