मराठी

Mr. Mehra sends his servant to the market to buy oranges worth Rs. 15. The servant having eaten three oranges on the way, Mr. Mehra pays Rs. 25 paise per orange more than the market price

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प्रश्न

Mr. Mehra sends his servant to the market to buy oranges worth Rs. 15. The servant having eaten three oranges on the way, Mr. Mehra pays Rs. 25 paise per orange more than the market price. Taking x to be the number of oranges which Mr. Mehra receives, form a quadratic equation in x. Hence, find the value of x.

बेरीज
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उत्तर

Number of oranges = y

Cost of one orange = Rs. 15/y

The servant ate 3 oranges, so Mr. Mehra received (y – 3) oranges.

So, x = y – 3

`\implies` y = x + 3  ...(1)

Cost of one orange paid by Mr. Mehra = Rs. `15/y + 0.25`

= Rs. `15/(x + 3) + 1/4`  ...[Using (1)]

Now, Mr. Mehra pays a total of Rs. 15

∴ `(15/(x + 3) + 1/4) xx x = 15`

`(60 + x + 3)/(4(x + 3)) xx x = 15`

63x + x2 = 60x + 180

x2 + 3x – 180 = 0

(x + 15)(x – 12) = 0

x = –15, 12

But, the number of oranges cannot be negative.

So, x = 12.

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पाठ 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (D) [पृष्ठ ७८]

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सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (D) | Q 8. | पृष्ठ ७८

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