Question

Match the following:

Column I	Column II
(a) a × 1	(i) Additive inverse of a
(b) 1	(ii) Additive identity
(c) (–a) ÷ (–b)	(iii) Multiplicative identity
(d) a × (–1)	(iv) a ÷ (–b)
(e) a × 0	(v) a ÷ b
(f) (–a) ÷ b	(vi) a
(g) 0	(vii) –a
(h) a ÷ (–a)	(viii) 0
(i) –a	(ix) –1

Answer 1

Column I	Column II
(a) a × 1	(vi) a
(b) 1	(iii) Multiplicative identity
(c) (–a) ÷ (–b)	(v) a ÷ b
(d) a × (–1)	(vii) – a
(e) a × 0	(viii) 0
(f) (–a) ÷ b	(iv) a ÷ (–b)
(g) 0	(ii) Additive identity
(h) a ÷ (–a)	(ix) –1
(i) –a	(i) Additive inverse of a

Explanation:

(a) a × 1 = a

(b) 1 = 1 is multiplicative identity.

(c) (–a) ÷ (–b) = a ÷ b  ...[Both signs are cancelled with each other]

(d) a × (–1) = a × (–1) = –a 

(e) a × 0 = 0  ...[Any value, when multiplies with 0 becomes zero]

(f) (–a) ÷ b = a ÷ (–b)

(g) 0 = 0 is an additive identity

(h) a ÷ (–a) = `a ÷ (-a) = a/(-a) = -1`

(i) –a = –a is additive inverse of a.