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प्रश्न
Marks of 60 students in a class are tabulated below. For finding mode the Lower limit of modal class (L) = --------
| Marks | 10 – 19 | 20 – 29 | 30 – 39 | 40 – 49 | 50 – 59 | 60 – 69 |
| Number of students | 3 | 8 | 16 | 12 | 10 | 8 |
बेरीज
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उत्तर
1. Identify the modal class
The modal class is the class interval with the highest frequency.
The maximum frequency is 16.
This corresponds to the class interval 30 – 39.
2. Convert to continuous class intervals
To find the exact value of L for the standard mode formula, the data must be continuous.
Adjustment factor = `("Lower limit of next class" - "Upper limit of current class")/2`
= `(20 - 19)/2`
= 0.5
Subtract 0.5 from each lower limit and add 0.5 to each upper limit:
| Marks (Original) |
Marks (Continuous) |
Number of students (Frequency) |
| 10 – 19 | 9.5 – 19.5 | 3 |
| 20 – 29 | 19.5 – 29.5 | 8 |
| 30 – 39 | 29.5 – 39.5 | 16 (Highest) |
| 40 – 49 | 39.5 – 49.5 | 12 |
| 50 – 59 | 49.5 – 59.5 | 10 |
| 60 – 69 | 59.5 – 69.5 | 8 |
3. Determine the Lower Limit (L)
In the continuous form, the modal class is 29.5 – 39.5.
Therefore, the precise lower boundary (L) used in the mode formula is 29.5.
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