मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Marks of 60 students in a class are tabulated below. For finding mode the Lower limit of modal class (L) = -------- Marks 10 – 19 20 – 29 30 – 39 40 – 49 50 – 59 60 – 69 Number of students 3 8 16 12

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प्रश्न

Marks of 60 students in a class are tabulated below. For finding mode the Lower limit of modal class (L) = --------

Marks 10 – 19 20 – 29 30 – 39 40 – 49 50 – 59 60 – 69
Number of students 3 8 16 12 10 8
बेरीज
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उत्तर

1. Identify the modal class

The modal class is the class interval with the highest frequency.

The maximum frequency is 16.

This corresponds to the class interval 30 – 39.

2. Convert to continuous class intervals

To find the exact value of L for the standard mode formula, the data must be continuous.

Adjustment factor = `("Lower limit of next class" - "Upper limit of current class")/2`

= `(20 - 19)/2`

= 0.5

Subtract 0.5 from each lower limit and add 0.5 to each upper limit:

Marks
(Original)
Marks
(Continuous)
Number of students
(Frequency)
10 – 19 9.5 – 19.5 3
20 – 29 19.5 – 29.5 8
30 – 39 29.5 – 39.5 16 (Highest)
40 – 49 39.5 – 49.5 12
50 – 59 49.5 – 59.5 10
60 – 69 59.5 – 69.5 8

3. Determine the Lower Limit (L)

In the continuous form, the modal class is 29.5 – 39.5.

Therefore, the precise lower boundary (L) used in the mode formula is 29.5.

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पाठ 6: Statistics - Q.1 (B)
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