Advertisements
Advertisements
प्रश्न
Make s the subject of the formula v2 = u2 + 2as. Find s when u = 3, a = 2 and v = 5.
Advertisements
उत्तर
v2 = u2 + 2as
⇒ v2 - u2 = 2as
⇒ s = `("v"^2 - "u"^2)/(2"a")`
Substituting u = 3, a = 2 and v = 5, we get
s = `(5^2 - 3^2)/(2 xx 2)`
= `(25 - 9)/(4)`
= `(16)/(4)`
= 4.
APPEARS IN
संबंधित प्रश्न
Make L the subject of formula T = `2pisqrt("L"/"G")`
Make x the subject of formula `"a"x^2/"a"^2 + y^2/"b"^2` = 1
Make a the subject of formula S = `("a"("r"^"n" - 1))/("r" - 1)`
Make a the subject of formula x = `sqrt(("a" + "b")/("a" - "b")`
Make V the subject of formula K = `(1)/(2)"MV"^2`
If A = pr2 and C = 2pr, then express r in terms of A and C.
If V = pr2h and S = 2pr2 + 2prh, then express V in terms of S, p and r.
Make h the subject of the formula R = `"h"/(2)("a" - "b")`. Find h when R = 108, a = 16 and b = 12.
The total energy E possess by a body of Mass 'm', moving with a velocity 'v' at a height 'h' is given by: E = `(1)/(2) "m" "u"^2 + "mgh"`. Make 'm' the subject of formula.
If s = `"n"/(2)[2"a" + ("n" - 1)"d"]`, the n express d in terms of s, a and n. find d if n = 3, a = n + 1 and s = 18.
