Question

मान ज्ञात कीजिए:

`sin (tan^-1 (-sqrt3) - sec^-1 2)`

Answer 1

हम जानते हैं कि,

`tan^-1 (-sqrt3) = -π/3  "तथा"  sec^-1 2 = π/3`

अतः,

`sin (tan^-1 (-sqrt3) - sec^-1 2) = sin (-π/3 - π/3) = sin (- (2π)/3)`

अब,

`sin (- (2π)/3) = - sin (2π)/3`

= `-sqrt3/2`

अतः अंतिम मान `-sqrt3/2` है।