Advertisements
Advertisements
प्रश्न
\[\lim_{x->0} \frac{e^x - 1}{x}\]=
पर्याय
e
nxn-1
1
0
Advertisements
उत्तर
1
APPEARS IN
संबंधित प्रश्न
Evaluate the following:
\[\lim_{x->∞} \frac{2x + 5}{x^2 + 3x + 9}\]
Evaluate the following:
`lim_(x->∞) (sum "n")/"n"^2`
If `lim_(x->a) (x^9 + "a"^9)/(x + "a") = lim_(x->3)` (x + 6), find the value of a.
Examine the following function for continuity at the indicated point.
f(x) = `{((x^2 - 4)/(x-2) "," if x ≠ 2),(0 "," if x = 2):}` at x = 2
Examine the following function for continuity at the indicated point.
f(x) = `{((x^2 - 9)/(x-3) "," if x ≠ 3),(6 "," if x = 3):}` at x = 3
Show that f(x) = |x| is continuous at x = 0.
Find the derivative of the following function from the first principle.
x2
Verify the continuity and differentiability of f(x) = `{(1 - x if x < 1),((1 - x)(2 - x) if 1 <= x <= 2),(3 - x if x > 2):}` at x = 1 and x = 2.
A function f(x) is continuous at x = a `lim_(x->"a")`f(x) is equal to:
If y = log x then y2 =
