Question

Light of wavelength 6000 Å falls on a single slit of width 0.1 mm. The second minimum will be formed for the angle of diffraction of ______.

पर्याय

• 0.08 rad

• 0.06 rad

• 0.12 rad

• 0.012 rad

Answer 1

Light of wavelength 6000 Å falls on a single slit of width 0.1 mm. The second minimum will be formed for the angle of diffraction of 0.012 rad.

Explanation:

Given single slit of width d = 0.1 mm

d = 0.1 × 10^-3 m

or d = 1 × 10^-4 m

Light of wavelength λ =  6000 Å

or λ = 6 × 10^-7 m

The angle of diffraction

θ = `("n"lambda)/"d"`

θ = `(2xx6xx10^-7)/(1xx10^-4)`

θ = 12 × 10^-3 

θ = 0.012 rad