Question

Let A = `[(4, -2),(6, -3)]`, B = `[(0, 2),(1, -1)]` and C = `[(-2, 3),(1, -1)]`. Find A² – A + BC

Answer 1

A² = `[(4, -2),(6, -3)][(4, -2),(6, -3)]`

= `[(16 - 12, -8 + 6),(24 - 18, -12 + 9)]`

= `[(4, -2),(6, -3)]`

BC = `[(0, 2),(1, -1)][(-2, 3),(1, -1)]`

= `[(0 + 2, 0 - 2),(-2 - 1, 3 + 1)]`

= `[(2, -2),(-3, 4)]`

Given, A² – A + BC

= `[(4, -2),(6, -3)] - [(4, -2),(6, -3)] + [(2, -2),(-3, 4)]`

= `[(0, 0),(0, 0)] +  [(2, -2),(-3, 4)]`

= `[(2, -2),(-3, 4)]`