मराठी
सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Joseph and Peter Can Complete a Work in 20 Hours and 25 Hours Respectively. Find : (I) Work Done by Both Together in 4 Hrs.

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प्रश्न

Joseph and Peter can complete a work in 20 hours and 25 hours respectively. Find :
(i) work done by both together in 4 hrs.
(ii) work left after both worked together for 4 hrs.
(iii) time taken by Peter to complete the remaining work.

बेरीज
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उत्तर

Joseph can do a work in = 20 hours

Peter can do the same work in = 25 hours

Now Joseph's 1 hour's work = `1/20`

and Peter's 1 hour's work = `1/25`

Both's 1 hour's work = `1/20 + 1/25 = (5 + 4)/100 = 9/100`

(i) Both's 4 hours work `= 9/100 xx 4 = 9/25`

(ii) Work left over `= 1 - 9/25`

`= (25 - 9)/25 = 16/25`

(iii) Peter can do `16/25` work in `= 25 xx 16/25` = 16 hours

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पाठ 7: Unitary Method (Including Time and Work) - Exercise 7 (C)

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सेलिना Concise Mathematics [English] Class 7 ICSE
पाठ 7 Unitary Method (Including Time and Work)
Exercise 7 (C) | Q 8

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