Question

It is given that m a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

Answer 1

Let E ⟶ event of 2 students having same birthday P(E) is given as 0.992

Let (`barE` ) ⟶ event of 2 students not having same birthday.

We know that, P(E) + P(`barE` ) = 1

P(`barE`) = 1 − 𝑃(𝐸)

= 1 – 0.992

= 0.008