Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x.
`1/(2x^2 - 9)`
बेरीज
Advertisements
उत्तर
`int 1/(2x^2 - 9) "d"x = int 1/((sqrt(2x))^2 - 3^2) "d"x`
Let t = `sqrt(2)x`
Then dt = `sqrt(2) "dt"`
= `1/2 int "dt"/("t"^2 - 3^2)`
= `1/sqrt(2) 1/(2(3)) log |("t" - 3)/("t" + 3)| + "c"`
= `1/(6sqrt(2)) log |(sqrt(2x) - 3)/(sqrt(2x) + 3)| + "c"`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
