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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

In the Representation of the Galvanic Cell, the Ions in the Same Phase Are Separated by a _______. - Chemistry

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प्रश्न

In the representation of the galvanic cell, the ions in the same phase are separated by a _______.

पर्याय

  • single vertical line

  • comma

  • double vertical line

  • semicolon

MCQ
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उत्तर

In the representation of the galvanic cell, the ions in the same phase are separated by a comma.

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2016-2017 (July)

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संबंधित प्रश्‍न

Draw a neat and well labelled diagram of primary reference electrode.


Arrange the following reducing agents in the order of increasing strength under standard state conditions. Justify the answer 

Element

Al(s)

Cu(s)

Cl(aq)

Ni(s)

 

Eo

-1.66V

0.34V

1.36V

-0.26V

 


Can copper sulphate solution be stored in an iron vessel? Explain.


The standard e.m.f of the following cell is 0.463 V

`Cu|Cu_(1m)^(++)`

What is the standard potential of Cu electrode?

(A) 1.137 V

(B) 0.337 V

(C) 0.463 V

(D) - 0.463 V


Calculate E°cell for the following reaction at 298 K:

2Al(s) + 3Cu+2(0.01M) → 2Al+3(0.01M) + 3Cu(s)

Given: Ecell = 1.98V


Calculate emf of the following cell at 25°C:

\[\ce{Sn/Sn^2+ (0.001 M) || H+ (0.01 M) | H2_{(g)} (1 bar) | Pt_{(s)}}\]

Given: \[\ce{E^\circ(Sn^2+/sn) = -0.14 V, E^\circ H+/H2 = 0.00 V (log 10 = 1)}\]


Calculate e.m.f of the following cell at 298 K:

2Cr(s) + 3Fe2+ (0.1M) → 2Cr3+ (0.01M) + 3 Fe(s)

Given: E°(Cr3+ | Cr) = – 0.74 VE° (Fe2+ | Fe) = – 0.44 V


Calculate emf of the following cell at 25 °C :

Fe|Fe2+(0.001 M)| |H+(0.01 M)|H2(g) (1 bar)|Pt (s)

E°(Fe2+| Fe)0.44 V E°(H+ | H20.00 V


 
 

Calculate e.m.f. and ∆G for the following cell:

Mg (s) |Mg2+ (0.001M) || Cu2+ (0.0001M) | Cu (s)

`"Given :" E_((Mg^(2+)"/"Mg))^0=−2.37 V, E_((Cu^(2+)"/"Cu))^0=+0.34 V.`

 

 
 

Depict the galvanic cell in which the reaction \[\ce{Zn(s) + 2Ag+(aq) → Zn^{2+}(aq) + 2Ag(s)}\] takes place. Further show:

  1. Which of the electrode is negatively charged?
  2. The carriers of the current in the cell.
  3. Individual reaction at each electrode.

Calculate the emf of the following cell at 25°C :

\[{E^0}_\left( {Zn}^{2 +} /Zn \right) = - 0 . 76 V, {E^0}_\left( H^+ / H_2 \right) = 0 . 00 V\]

 


Galvanic or a voltaic cell converts the chemical energy liberated during a redox reaction to ____________.


Standard hydrogen electrode operated under standard conditions of 1 atm Hpressure, 298 K, and pH = 0 has a cell potential of ____________.


Using the data given below find out the strongest reducing agent.

`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖` = 1.33 V  `"E"_("Cl"_2//"Cl"^-) = 1.36` V

`"E"_("MnO"_4^-//"Mn"^(2+))` = 1.51 V  `"E"_("Cr"^(3+)//"Cr")` = - 0.74 V


Use the data given in below find out which of the following is the strongest oxidising agent.

`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖`= 1.33 V `"E"_("Cl"_2//"Cl"^-)^⊖` = 1.36 V

`"E"_("MnO"_4^-//"Mn"^(2+))^⊖` = 1.51 V `"E"_("Cr"^(3+)//"Cr")^⊖` = - 0.74 V


The positive value of the standard electrode potential of Cu2+/Cu indicates that:

(i) this redox couple is a stronger reducing agent than the H+/H2 couple.

(ii) this redox couple is a stronger oxidising agent than H+/H2 .

(iii) Cu can displace H2 from acid.

(iv) Cu cannot displace H2 from acid.


What does the negative sign in the expression `"E"^Θ ("Zn"^(2+))//("Zn")` = − 0.76 V mean?


Which reference electrode is used to measure the electrode potential of other electrodes?


Represent the cell in which the following reaction takes place.The value of E˚ for the cell is 1.260 V. What is the value of Ecell?

\[\ce{2Al (s) + 3Cd^{2+} (0.1M) -> 3Cd (s) + 2Al^{3+} (0.01M)}\]


Standard electrode potential of three metals X, Y and Z are –1.2 V, +0.5 V and –3.0 V, respectively. The reducing power of these metals will be ______.


The potential of a hydrogen electrode at PH = 10 is


The emf of a galvanic cell, with electrode potential of Zn2+ = - 0.76 V and that of Cu2+ = 0.34 V, is ______.


A voltaic cell is made by connecting two half cells represented by half equations below:

\[\ce{Sn^{2+}_{ (aq)} + 2e^- -> Sn_{(s)}}\], E0 = − 0.14 V

\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\], E0 = + 0.77 V

Which statement is correct about this voltaic cell?


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