Question

In the potentiometer experiment, cells of e.m.f. E₁ and E₂ are connected in series (E₁ > E₂). the balancing length is 64 cm of the wire. If the polarity of E₂ is reversed, the balancing length becomes 32 cm. The ratio `E_1/E_2` is ______   

पर्याय

• 1 : 2

• 1 : 3

• 2 : 1

• 3 : 1

Answer 1

In the potentiometer experiment, cells of e.m.f. E₁ and E₂ are connected in series (E₁ > E₂). the balancing length is 64 cm of the wire. If the polarity of E₂ is reversed, the balancing length becomes 32 cm. The ratio `E_1/E_2` is 3 : 1.

Explanation:

`E_1/E_2 = (ℓ_1 + ℓ_2)/(ℓ_1 - ℓ_2) = (64 + 32)/(64 - 32) = 96/32 = 3`