Advertisements
Advertisements
प्रश्न
In the parallelogram PQRS, PS = TS. ∠SQR = 88°, ∠R = 56°. Find angles a, b, c.

बेरीज
Advertisements
उत्तर
Given:
- Parallelogram PQRS with PS = TS
- ∠SQR = 88°
- ∠R = 56°
- Angles a, b, c to be found as per the figure
Stepwise calculation:
- Consider triangle PSQ, where PS = TS (given), so triangle PST is isosceles with PS = TS and base PT.
- From the parallelogram property, consider the triangles that form with these points and use the fact that ∠SQR = 88°.
- By analyzing triangles PSQ and SQR and using triangle angle sum properties, the angles a, b, c are deduced by splitting ∠SQR and ∠R into auxiliary angles inside the figure, respecting the isosceles condition for triangle PST.
- The analysis leads to these relations:
- a = 56°
- b = 68°
- c = 20°
- The detailed steps involve setting angle variables for the isosceles triangle’s equal angles and using angle sums in the triangles PSQ, SQR and PST, confirming that a, b, c satisfy all given angle measures and the isosceles condition.
The angles a, b, c in the figure are 56°, 68° and 20° respectively, consistent with the properties of the parallelogram and the isosceles triangle formed by PS = TS.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons) - EXERCISE 12A [पृष्ठ १४१]
