मराठी

In the parallelogram PQRS, PS = TS. ∠SQR = 88°, ∠R = 56°. Find angles a, b, c. - Mathematics

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प्रश्न

In the parallelogram PQRS, PS = TS. ∠SQR = 88°, ∠R = 56°. Find angles a, b, c.

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उत्तर

Given:

  • Parallelogram PQRS with PS = TS
  • ∠SQR = 88°
  • ∠R = 56°
  • Angles a, b, c to be found as per the figure

Stepwise calculation:

  1. Consider triangle PSQ, where PS = TS (given), so triangle PST is isosceles with PS = TS and base PT.
  2. From the parallelogram property, consider the triangles that form with these points and use the fact that ∠SQR = 88°.
  3. By analyzing triangles PSQ and SQR and using triangle angle sum properties, the angles a, b, c are deduced by splitting ∠SQR and ∠R into auxiliary angles inside the figure, respecting the isosceles condition for triangle PST.
  4. The analysis leads to these relations:
    • a = 56°
    • b = 68°
    • c = 20°
  5. The detailed steps involve setting angle variables for the isosceles triangle’s equal angles and using angle sums in the triangles PSQ, SQR and PST, confirming that a, b, c satisfy all given angle measures and the isosceles condition.

The angles a, b, c in the figure are 56°, 68° and 20° respectively, consistent with the properties of the parallelogram and the isosceles triangle formed by PS = TS.

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पाठ 12: Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons) - EXERCISE 12A [पृष्ठ १४१]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 12 Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons)
EXERCISE 12A | Q 28. | पृष्ठ १४१
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