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प्रश्न
In the nuclear fusion reaction
\[\ce{^2_1H + ^3_1H-> ^4_2He + n}\]
given that the repulsive potential energy between the two nuclei is ∼ 7.7 × 10-14J, the temperature at which the gases must be heated to initiate the reaction is nearly
[Boltzmann's Constant k = 1.38 × 10-23 J/K]
पर्याय
107 K
105 K
103 K
109 K
MCQ
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उत्तर
109 K
Explanation:
The average kinetic energy per molecule at temperature T is = `3/2`kT
Where k = Boltzmann's constant
This kinetic energy should be able to provide the repulsive potential energy
∴ `3/2`kT = 7.7 × 10-14
⇒ T = `(2xx7.7xx10^-14)/(3xx1.38xx10^-23)`
= 3.7 × 109 K
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Mass-Energy Equivalence and Nuclear Reactions
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