मराठी

In the nuclear fusion reaction A12A2122H+A13A2123H⟶A24A2224He+n given that the repulsive potential energy between the two nuclei is ∼ 7.7 × 10-14J,

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प्रश्न

In the nuclear fusion reaction

\[\ce{^2_1H + ^3_1H-> ^4_2He + n}\]

given that the repulsive potential energy between the two nuclei is ∼ 7.7 × 10-14J, the temperature at which the gases must be heated to initiate the reaction is nearly

[Boltzmann's Constant k = 1.38 × 10-23 J/K]

पर्याय

  • 107 K

  • 105 K

  • 103 K

  • 109 K

MCQ
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उत्तर

109 K

Explanation:

The average kinetic energy per molecule at temperature T is = `3/2`kT

Where k = Boltzmann's constant

This kinetic energy should be able to provide the repulsive potential energy

∴ `3/2`kT = 7.7 × 10-14

⇒ T = `(2xx7.7xx10^-14)/(3xx1.38xx10^-23)`

= 3.7 × 10K

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Mass-Energy Equivalence and Nuclear Reactions
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