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प्रश्न
In the given graph, P and Q are points such that PQ cuts off intercepts of 5 units and 3 units along the x-axis and y-axis respectively. Line RS is perpendicular to PQ and passes through the origin. Find the:
- coordinates of P and Q
- equation of line RS

बेरीज
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उत्तर
(a) From the graph
The coordinates of
P = (5, 0)
Q = (0,−3)
(b) Slope of PQ (m1) = `(y_2 − y_1)/(x_2 − x_1)`
Slope of PQ (m1) = `(y_2 − y_1)/(x_2 − x_1)`
Since line RS is perpendicular to PQ the slopе
m2 of RS is
m1 − m2 = −1
m2 = `−1/3 = (−5)/3`
m2 = `3/5`
Now, equation of line RS passing through origin (0, 0)
(y − y1) = `(−5)/3 (x − x_1)`
`(y − 0) = (−5)/3 (x − 0)`
3y + 5x = 0
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