मराठी

In the given figure, the line segment AB meets x-axis at A and y-axis at B. The point \(\mathrm{P}(–3, 1)\) on AB divides it in the ratio 2 : 3. Find the co-ordinates of A and B.

Advertisements
Advertisements

प्रश्न

In the given figure, the line segment AB meets x-axis at A and y-axis at B. The point \(\mathrm{P}(-3, 1)\) on AB divides it in the ratio 2 : 3. Find the co-ordinates of A and B.
[Hint: (i) The co-ordinates of A and B are of the form A(x, 0), and B(0, y).]

बेरीज
Advertisements

उत्तर

Let $$A(x, 0)$$ and $$B(0, y)$$.

Since $$P(-3, 1)$$ divides AB in the ratio $$2 : 3$$, the co-ordinates of P are $$\left(\frac{2 \times 0 + 3 \times x}{2 + 3}, \frac{2 \times y + 3 \times 0}{2 + 3}\right)$$

Comparing with $$P(-3, 1)$$:

$$\frac{3x}{5} = -3$$

$$\Rightarrow x = -5$$

$$\frac{2y}{5} = 1$$

$$\Rightarrow y = \frac{5}{2}$$

Hence the co-ordinates of A are $$A(-5, 0)$$ and of B are $$B\left(0, \frac{5}{2}\right)$$.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Section and Mid-point Formulae - EXERCISE 13 [पृष्ठ २१०]

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10 ICSE
पाठ 13 Section and Mid-point Formulae
EXERCISE 13 | Q 17. | पृष्ठ २१०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×