मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

In the given figure, seg PA, seg QB, seg RC, and seg SD are perpendicular to line AD. AB = 60, BC = 70, CD = 80, PS = 280 then Find PQ, QR, and RS.

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प्रश्न

In the given figure, seg PA, seg QB, seg RC, and seg SD are perpendicular to line AD.

AB = 60, BC = 70, CD = 80, PS = 280 then find PQ, QR, and RS. 

बेरीज
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उत्तर

`{:("seg PA, seg QB, seg RC, and seg SD are perpendicular to line AD."),("AB = 60, BC = 70, CD = 80, PS = 280"):} ...}"Given"`

AD = AB + BC + CD

∴ AD = 60 + 70 + 80

∴ AD = 210

The lines PA, QB, RC, and SD are parallel to each other.

The Intercept theorem provides the ratios between the line segments created when two parallel lines are intercepted by two intersecting lines.

By the Intercept Theorem,

`"PQ"/"AB" = "QR"/"BC" = "RS"/"CD" = "PS"/"AD"`

∴ `"PQ"/60 = "QR"/70 = "RS"/80 = 280/210`

Considering `"PQ"/60 = 280/210`,

∴ `"PQ"/60 = 280/210`

∴ `"PQ" = (280 × 60)/210`

∴ PQ = 80

Considering `"QR"/70 = 280/210`

∴  `"QR"/70 = 280/210`

∴  `"QR" = (280 × 70)/210`

∴  `"QR" = 280/3`

Considering `"RS"/80 = 280/210`

∴ `"RS"/80 = 280/210`

∴ `"RS" = (280 × 80)/210`

∴ `"RS" =320/3`

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Property of Three Parallel Lines and Their Transversals
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पाठ 1: Similarity - Problem Set 1 [पृष्ठ २८]
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