Advertisements
Advertisements
प्रश्न
In the following figure QP || RT. Find the values of x and y.
Advertisements
उत्तर
QP || RT and PR is a transversal.
∴ ∠QPR = ∠PRT ...[Alternate interior angles]
⇒ x = 70°
Now, QP || RT and QR is a transversal.
∴ ∠PQR + ∠QRT = 180° ...[Co-interior angles]
⇒ 30° + y + 70° = 180°
⇒ y = 180° – 30° – 70° = 80°
Thus, x = 70° and y = 80°.
APPEARS IN
संबंधित प्रश्न
Find the value of the unknown exterior angle x in the following diagram:
∠ACD is an exterior angle of ∆ABC. The measures of ∠A and ∠B are equal. If m∠ACD = 140°, find the measures of the angles ∠A and ∠B.
Find the value of x in the given triangle
An exterior angle of a triangle is 70° and two interior opposite angles are equal. Then measure of each of these angle will be
If the exterior angle of a triangle is 140° and its interior opposite angles are equal, find all the interior angles of the triangle
In the given figure BD = BC, find the value of x
In the following figure,
- ∠TPQ = ∠ _____ + ∠ _____.
- ∠UQR = ∠ _____ + ∠ _____.
- ∠PRS = ∠ _____ + ∠ _____.
Find the measure of ∠A in the following figure.
Find the value of x in the following figure.
What is the measure of an exterior angle if its adjacent interior angle measures 65∘?
