Advertisements
Advertisements
प्रश्न
In the given figure find the values of x and y
Advertisements
उत्तर
In ∆BCA, ∠BAX = 62° is the exterior angle at A
Exterior angle = sum of interior opposite angles
∠ABC + ∠ACB = ∠BAX
28° + x = 62°
x = 62° – 28°
= 34°
Also ∠BAC + ∠BAX = 180° ...[∵ Linear pair]
y + 62° = 180°
y = 180° – 62°
= 118°
x = 34°
y = 118°
APPEARS IN
संबंधित प्रश्न
Find the value of the unknown exterior angle x in the following diagram:
Find the value of the unknown interior angle x in the following figure.
Find the value of the unknown interior angle x in the following figure.
In the isosceles triangle ABC, ∠A, and ∠B are equal. ∠ACD is an exterior angle of ∆ABC. The measures of ∠ACB and ∠ACD are (3x − 17)° and (8x + 10)°, respectively. Find the measures of ∠ACB and ∠ACD. Also find the measures of ∠A and ∠B.
In ∆LMN, MN is extended to O. If ∠MLN = 100 – x, ∠LMN = 2x and ∠LNO = 6x – 5, find the value of x
Using the given figure find the value of x.
In the given figure BD = BC, find the value of x
If the exterior angle of a triangle is 130° and its interior opposite angles are equal, then measure of each interior opposite angle is ______.
In ∆ABC, ∠Α = 50°, ∠B = 70° and bisector of ∠C meets AB in D (see figure). Measure of ∠ADC is ______.
If all three sides of a triangle are extended, how many distinct exterior angles are formed in total?
