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प्रश्न
In the given figure (each observation is in cm) tan C is:

पर्याय
`3/5`
`4/3`
`3/4`
`4/5`
MCQ
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उत्तर
`bb(3/4)`
Explanation:
In the right-angled triangle ABD, the hypotenuse AB = 26 and base BD = 10. Using the Pythagorean theorem, the perpendicular altitude AD is:
\[\text{AD} = \sqrt{\text{AB}^2 - \text{BD}^2} = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24\text{ cm}\]
In triangle ADC, the base DC = 32 and altitude AD = 24. Therefore, tanC is:
\[\tan\text{C} = \frac{\text{Perpendicular}}{\text{Base}} = \frac{\text{AD}}{\text{DC}} = \frac{24}{32} = \frac{3}{4}\]
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