Advertisements
Advertisements
प्रश्न
In the given figure, DE and DF are tangents from an external point D to a circle with centre A. If DE = 5 cm and DE ⊥ DF then the radius of the circle is ______.
पर्याय
3 cm
4 cm
5 cm
6 cm
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
In the given figure, DE and DF are tangents from an external point D to a circle with centre A. If DE = 5 cm and DE ⊥ DF then the radius of the circle is 5 cm.
Explanation:
Join AE and AF. Then, AFDE is a square.
∴ Radius of circle = AE = DE = 5 cm.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
