Question

In the given figure, AD is perpendicular to BC. Find: 15 tan y

Answer 1

ΔADB is a right-angled triangle.
∴ AB²
= AB² + BD²
= 12² + 16²
= 144 + 256
= 400
⇒ AB = 20cm
ΔADC is a right-angled triangle.
∴ AC²
= AD² + DC²
= 12² + 9²
= 144 + 81
= 225
⇒ AC = 15cm
15 tan y

= `15 xx "CD"/"AD"`

= `15 xx (9)/(12)`

= `(45)/(4)`.